(7^-4)n=(1)/(7^8)

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Solution for (7^-4)n=(1)/(7^8) equation:



(7^-4)n=(1)/(7^8)
We move all terms to the left:
(7^-4)n-((1)/(7^8))=0
We multiply parentheses
7n^2-4n-(1/7^8)=0
We get rid of parentheses
7n^2-4n-1/7^8=0
We multiply all the terms by the denominator
7n^2*7^8-4n*7^8-1=0
Wy multiply elements
49n^10-28n^9-1=0
We do not support enpression: n^10

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